#P3532. [POI2012] ODL-Distance
[POI2012] ODL-Distance
题目描述
We consider the distance between positive integers in this problem, defined as follows.
A single operation consists in either multiplying a given number by a prime number1 or dividing it by a prime number (if it does divide without a remainder).
The distance between the numbers and , denoted , is the minimum number of operations it takes to transform the number into the number .
For example, .
Observe that the function is indeed a distance function - for any positive integers , and the following hold:
the distance between a number and itself is 0: , the distance from to is the same as from to : , and the triangle inequality holds: .
A sequence of positive integers, , is given.
For each number we have to determine such that and is minimal.
给你一个序列a[],定义d(i,j)=a[i],a[j]每次操作可以对其中之一乘一个质数p或除以一个数p(p必须为被除数的约数),让a[i]=a[j]的最少操作步数
对于每个i,求d(i,j)最小的j,若有多个解,输出最小的j
输入格式
In the first line of standard input there is a single integer ().
In the following lines the numbers () are given, one per line.
In tests worth 30% of total point it additionally holds that .
输出格式
Your program should print exactly lines to the standard output, a single integer in each line.
The -th line should give the minimum such that: , and is minimal.
6
1
2
3
4
5
6
2
1
1
2
1
2
提示
给你一个序列a[],定义d(i,j)=a[i],a[j]每次操作可以对其中之一乘一个质数p或除以一个数p(p必须为被除数的约数),让a[i]=a[j]的最少操作步数
对于每个i,求d(i,j)最小的j,若有多个解,输出最小的j