#P11676. [USACO25JAN] DFS Order P

[USACO25JAN] DFS Order P

Description

Bessie has a simple undirected graph with vertices labeled 1N1\dots N (2N7502\le N\le 750). She generates a depth-first search (DFS) order of the graph by calling the function dfs(1)\texttt{dfs}(1), defined by the following C++ code. Each adjacency list (adj[i]\texttt{adj}[i] for all 1iN1\le i\le N) may be permuted arbitrarily before starting the depth first search, so a graph can have multiple possible DFS orders.

vector<bool> vis(N + 1);
vector<vector<int>> adj(N + 1);  // adjacency list
vector<int> dfs_order;

void dfs(int x) {
    if (vis[x]) return;
    vis[x] = true;
    dfs_order.push_back(x);
    for (int y : adj[x]) dfs(y);
}

You are given the initial state of the graph as well as the cost to change the state of each edge. Specifically, for every pair of vertices (i,j)(i,j) satisfying 1i<jN1\le i<j\le N, you are given an integer ai,ja_{i,j} (0<ai,j10000<|a_{i,j}|\le 1000) such that

  • If ai,j>0a_{i,j}>0, edge (i,j)(i,j) is not currently in the graph, and can be added for cost ai,ja_{i,j}.
  • If ai,j<0a_{i,j}<0, edge (i,j)(i,j) is currently in the graph, and can be removed for cost ai,j-a_{i,j}.

Determine the minimum total cost to change the graph so that [1,2,N][1,2\dots,N] is a possible DFS ordering.

Input Format

The first line contains NN.

Then N1N-1 lines follow. The j1j-1th line contains a1,j,a2,j,,aj1,ja_{1,j}, a_{2,j}, \dots, a_{j-1,j} separated by spaces.

Output Format

The minimum cost to change the graph so that [1,2,,N][1,2,\dots, N] is a possible DFS ordering.

4
1
2 3
40 6 11
10
5
-1
10 -2
10 -7 10
-6 -4 -5 10
5
4
-1
-2 300
4 -5 6
9

Hint

For Sample 1:

Initially, the graph contains no edges. (1,2),(2,3),(2,4)(1,2),(2,3),(2,4) can be added for a total cost of 1+3+61+3+6. The graph now has two possible DFS orderings: [1,2,3,4],[1,2,4,3][1,2,3,4],[1,2,4,3].

For Sample 2:

Initially, the graph contains edges (1,2),(2,3),(2,4),(1,5),(2,5),(3,5)(1,2),(2,3),(2,4),(1,5),(2,5),(3,5). Edge (3,5)(3,5) can be removed for a cost of 55.

For Sample 3:

Initially, the graph contains edges (1,2),(1,3),(2,4)(1,2),(1,3),(2,4). Edge (2,4)(2,4) can be removed and edge (1,4)(1,4) can be added for a total cost of 5+4=95+4=9.

SCORING:

  • Inputs 4-9: All ai,j>0a_{i,j}>0
  • Inputs 10-16: N50N\le 50
  • Inputs 17-23: No additional constraints.